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JSpart1.js

Live

// Do these meetings conflict?
function hasConflict(meetings) {
  meetings.sort((a,b) => a[0] - b[0]);
  for (let i = 1; i < meetings.length; i++) {
    if (meetings[i][0] < meetings[i-1][1]) {
      return true;
    }
  }
  return false;
}

JavaScript Connected

OUTPUT

Test 1: passed

Test 2: failed

Test 2: passed

🧑‍🏫Tim

Alright, meeting conflicts—how would you tackle this?

Sort by start, then scan for overlaps.

Nice. Check that boundary—off by one?

Part 1

[[7,10], [2,4]] → true

[[0,30], [5,10], [15,20]] → false

[[1,2], [2,3], [3,4]] → true

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JSsolution.js

Connected

function hasConflict(meetings) {
  meetings.sort((a,b) => a[0] - b[0]);
  for (let i = 1; i < meetings.length; i++) {
    if (meetings[i][0] < meetings[i-1][1]) 
      return true;
  }
  return false;
}

Run Code

Output

Test 1: [[7,10],[2,4]] → true

Test 2: [[0,30],[5,10]] → false

Test 3: [[1,2],[2,3]] → true

Executed in 0.8s · Memory: 12.4 MB

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